if (a+x)( x-3)= xsquare +6x+p then find the value of p
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Answer:
(x + a)(x-3) = x²+6x+p
x(x-3) + a(x-3)= x²+6x+p
x²-3x + ax -3a= x²+6x+p
x² +(-3+a)x+(-3a) = x²+6x+p
Comparing both sides we get,
-3 + a= 6
a=6+3=9
and
-3a= p
-3(9) =p
so p= -27
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Answer:
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