Question

If A = {x:x є N, x < 5} and B = {y:y is a factor of 6},
n(AՈB) = n (A-B) + n (B-A)
n(A’) = 60, n(B) = 70, and n(AՈB) = 20, find n((AUB)’).​

Answer 1

Step-by-step explanation:

A = { 1, 2, 3, 4 }

B = { 1, 2, 3, 6, }

hope it helps✌✌

Answer 2

Answer:

n (A Intersection B) = n (A)+n (B)-n (AUB)

20= (60)+70-n(AUB)

n (AUB) = 130-20

n (AUB)= 110.

Hope it helps u mate

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