Question

if a^x = (x+y+z)^y , a^y = (x+y+z)^z and a^z = (x+y+z)^x then prove that x+y+z = a

Answer 1

Answer:

a^x = (x+y+z)^y , a^y = (x+y+z)^z

a^z = (x+y+z)^x

a^x×a^y×a^z=(x+y+z)^y(x+y+z)^z(x+y+z)^x

a^(x+y+z) =(x+y+z)^x+y+z

a=(x+y+z)^(x+y+z) /(x+y+z)

a=x+y+z

x+y+z = a