Math, asked by abcd1029, 3 months ago

If A = {x:x² - 16=0,XER} and B = {x:x² - 5x+6=0, XER} then
find AUB, AnB, A-B, B-A.

Answers

Answered by rajitagupta05
7

Step-by-step explanation:

A=x²-16=0

x²=16

x=+-4

B=x²-5x+6=0

x=2,3

AUB={(4,2) (4,3) (-4,2) (-4,3)}

AnB =Phi

A-B= {4,-4}

B-A= {2,3}

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