Question

if a{x:xis a root of x²-5x+6=0}then number of subsets to a?​

Answer 1

Answer:

x^2-3x-2x+6=0 x(x-3)-2(x-3) =0 (x-3)(x-2) =0 x-3=0 or x-2=0 x=3 or x=2

Step-by-step explanation:

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