if a/ (x-y)= b/(y-z)= c/(z-x), find the value of a+b+c
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Step-by-step explanation:
a/x-y = b/y-z = c/z-x
first value of a is
a = {b(x-y)}/y-z = c/z-x
a = {c(y-z)}/[z-x][by-bz]
- a = (cy-cz)/[z-x][by-bz]
second value of b
b/y-z = a/x-y = c/z-x
b = {a(y-z)}/x-y = c/z-x
2. b = {c(x-y)}/[z-x][ay-az]
third value of c
c = b(z-x)/y-z = a/x-y
3 .c = {a(y-z)}/[x-y][bz-bx]
I have given you the value of a, b & c
now you can equate a+b+c
Thanku
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