Math, asked by shailvigracymaj9, 10 months ago

if a/ (x-y)= b/(y-z)= c/(z-x), find the value of a+b+c

Answers

Answered by amitkumarjhaadv
2

Step-by-step explanation:

a/x-y = b/y-z = c/z-x

first value of a is

a = {b(x-y)}/y-z = c/z-x

a = {c(y-z)}/[z-x][by-bz]

  1. a = (cy-cz)/[z-x][by-bz]

second value of b

b/y-z = a/x-y = c/z-x

b = {a(y-z)}/x-y = c/z-x

2. b = {c(x-y)}/[z-x][ay-az]

third value of c

c = b(z-x)/y-z = a/x-y

3 .c = {a(y-z)}/[x-y][bz-bx]

I have given you the value of a, b & c

now you can equate a+b+c

Thanku

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