IF A(x,y) is a point on the line joining the points B(2,-3) and C(-4,5) and A is equilateral from B and C then prove that 3x-4y+7+0
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We are going to find slope of AB
m
AB
=
−4−2
5−(−3)
⇒ m
AB
=
−6
8
∴ m
AB
=
3
−4
Now,
m
L
×m
AB
=−1
⇒ m
L
×(
3
−4
)=−1
⇒ m
L
=
4
3
The required equation,
⇒ y−y
1
=m
L
(x−x
1
)
⇒ y−(−3)=
4
3
(x−2)
⇒ 4(y+3)=3x−6
⇒ 4y+12=3x−6=0
⇒ 3x−4y−18=0
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