If a=x1/3y1/3+x-1/3y-1/3 then a3-3ay-x is equal to
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a=x^1/3.y^1/3+x^(-1/3).y^(-1/3) find a^3-3ay-x=
________________________________________________________
[Solution is in the attachment]
Here in this question we have to assume the value of X & y.
I have assume x= 8 & y= 1
____________________________________________________________________________________
Solution is = a³-3ay-x=
0.125= 125/1000= 1/8
____________________________________________________________________________________
Hope this will help you.....
a=x^1/3.y^1/3+x^(-1/3).y^(-1/3) find a^3-3ay-x=
________________________________________________________
[Solution is in the attachment]
Here in this question we have to assume the value of X & y.
I have assume x= 8 & y= 1
____________________________________________________________________________________
Solution is = a³-3ay-x=
0.125= 125/1000= 1/8
____________________________________________________________________________________
Hope this will help you.....
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answer is 1/8
thanks
thanks
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