Math, asked by Bumblebeez02, 1 day ago

If a,x1,x2 are in GP with common ratio 'r' and b,y1,y2 are in GP with common ratio 's' where s-r=2 then the area of the triangle with vertices (a,b), (x1,y1), (x2,y2) is

Answers

Answered by uchhetri107
0

Answer:

a,x1,x2 are in GP with common ratio 'r' and b,y1,y2 are in GP with common ratio 's' where s-r=2 then the area of the triangle with vertices (a,b), (x1,y1), (x2,y2) is

Step-by-step explanation:

a,x1,x2 are in GP with common ratio 'r' and b,y1,y2 are in GP with common ratio 's' where s-r=2 then the area of the triangle with vertices (a,b), (x1,y1), (x2,y2) is

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