If A(x1, y1) , B(x2, y2) , C(x3, y3) are the vertices of a parallelogram, how many possible positions of fourth vertex D exists?
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We know that in the parallelogram the diagonals bisect each other:
A = (x₁,y₁)
B = (x₂,y₂)
C = (x₃,y₃)
D = (x,y)
Here the midpoint of the line would be AC = (x₁+x₃)/2
And the midpoint of the line BD = x₁ + x/2
x₁ + x₃/₂ = x+x₂/2
x = x₁+x₃+x₂
y₁ +y₃ = y₂ + y/2
y = y₁ + y₃ + y₂
So the coordinates for D will be (x₁+x₃+x₂,y₁+y₃+y₂)
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