Question

if A= x²+xy‐6,B= 6xy‐2x²+1,C= 3x²+7‐3xy, find A‐B+C​

Answer 1

Given that,

A = x² + xy - 6

B = 6xy - 2x² + 1

C = 3x² + 7 - 3xy

: A + B + C

= (x² + xy - 6) + (6xy - 2x² + 1) + (3x² + 7 - 3xy)

= x² + xy - 6 + 6xy - 2x² + 1 + 3x² + 7 - 3xy

= 2x² + 4xy + 2