If a , ß, y are the roots of the equation x3 + px? + r = 0. Find
the value of c? + B2 + y2
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Answer:
Put y=x3 in the equation x3+r=−px2−qx
⇒y+r=−x(px+q)
⇒(y+r)3=−x3(px+q)3
⇒(y+r)3=−y(p3x3+q3+3p2qx2+3pq2x)
⇒(y+r)3=−y(p3y+q3+3pq(px2+qx))
⇒(y+r)3=−y(p3y+q3+3pq(−x3−r))
⇒(y+r)3=−y(p3y+q3+3pq(−y−r))
⇒y3+(3r+p
hope it helps you
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