If a/y-z=b/x-z=c/x-y; then ax+by+CZ=?
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Ax+ by +cz is equal to 3
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The answer is zero.
a/y = b/x
if a/y - z = c/x - y
then a/y - z + y = c/x
and (a - zy + y^2)/y = c/x
(a - zy)/y = (c - yx)/x
so: a = a - zy = z - zy + y^2
if b = c = c - yx
so y = 0
and so by = 0 = ax
and z = y = 0
so ax + by + CZ = 0
a/y = b/x
if a/y - z = c/x - y
then a/y - z + y = c/x
and (a - zy + y^2)/y = c/x
(a - zy)/y = (c - yx)/x
so: a = a - zy = z - zy + y^2
if b = c = c - yx
so y = 0
and so by = 0 = ax
and z = y = 0
so ax + by + CZ = 0
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