Question

If a zero of p(x) =x2+kx+8 is 2 find the value of k

Answer 1

Answer:

The zero of the polynomial x²+kx+8 is 2

Then P(2)=>(2)²+k(2)+8=0

=>4+2k=-8

=>2k=-8-4

=>k=-12/2

k=-6

The value of k is -6

Hope this helps you friend

Answer 2

Step-by-step explanation:

this the answer

here k=6