Question

If a1 =- 1 then find a2 a3 in an=an-1/n+2, n;1 n € n

Answer 1

Answer:

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Answer 2

Answer:

The value of  a₂  = $\frac{-1}{4}$

The value of  a₃ = $\frac{-1}{20}$

Step-by-step explanation:

Given,

The value of a₁ = -1

aₙ = $\frac{a_{n-1}}{n+2}$

To find,

The values of a₂ and a₃

Solution:

The value of a₂ and a₃ can be calculated by substituting the value of n as 2 and 3 in aₙ

we have aₙ = $\frac{a_{n-1}}{n+2}$

Substituting the value of n as 2 we get

a₂ = $\frac{a_{2-1}}{2+2}$ = $\frac{a_{1}}{4}$

Substituting the value of a₁ = -1, we get

a₂ = $\frac{a_{1}}{4}$ = $\frac{-1}{4}$

The value of  a₂  = $\frac{-1}{4}$

Substituting the value of n as 3 we get

a₃ = $\frac{a_{3-1}}{3+2}$ = $\frac{a_{2}}{5}$

Substituting the value of a₂  = $\frac{-1}{4}$ , we get

a₃= $\frac{a_{2}}{5}$ = $\frac{-1}{20}$

The value of  a₃ = $\frac{-1}{20}$

∴The value of  a₂  = $\frac{-1}{4}$

The value of  a₃ = $\frac{-1}{20}$

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