Question

If a1 = √3 and a6=5√3 find s6​

Answer 1

Answer:

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Step-by-step explanation:

$a6 = a1 + 5d = > 5 \sqrt{3} = \sqrt{3} + 5d \\ = > 5 \sqrt{3} - \sqrt{3} = 5d \\ = > 5d = 4 \sqrt{3} = > d = \frac{4 \sqrt{3} }{5}$

$s6 = \frac{6}{2} (2( \sqrt{3} ) + (6 - 1) \frac{4 \sqrt{3} }{5} ) \\ s6 = 3(2 \sqrt{3} + 4 \sqrt{3} ) \\ s6 = 3(6 \sqrt{3} ) = > s6 = 18 \sqrt{3}$