if a1/3+b1/3+c1/3 =0 then find a+b+c
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a1/3+b1/3+c1/3=0
=>a/3+b/3+c/3=0
=>(a+b+c)/3=0
=>a+b+c=0/3
=>a+b+c=0
=>a/3+b/3+c/3=0
=>(a+b+c)/3=0
=>a+b+c=0/3
=>a+b+c=0
Answered by
1
HERE
a1/3+b1/3+c1/3 =0
or,(3a+1)/3+(3b+1)/3+(3c+1)/3=0
or,(3a+1+3b+1+3c+1)/3=0
or,3a+3b+3c+3=0
or,3(a+b+c)=-3
a+b+c=-1
a1/3+b1/3+c1/3 =0
or,(3a+1)/3+(3b+1)/3+(3c+1)/3=0
or,(3a+1+3b+1+3c+1)/3=0
or,3a+3b+3c+3=0
or,3(a+b+c)=-3
a+b+c=-1
abhimanyu20:
it is wrong
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