Question

If a1, a2.............,a24 are in
A.P and
a1 +a5 + a10 + a15+ a 20 + a 24 = 225
then a1 +a2+a3 +.......... +a24=
-

Answer 1

Step-by-step explanation:

a=a1= first term

d= common difference = 2a-1a

= a

n = number of terms = 24

sum of ap = n/2(2a+(n-1) d)

s24= 24/2(2(a1)+(24-1)a)

= 12(2a+23a)

=12(25a)

= 300a