Question

If a1 a2 a3 a4 a5 a6 a7 are unique integers such that a2/2! +a3/3!

Answer 1

Answer:

by evaluating, we will find, a2 = 1, a3 = 1, a4 = 1, a5 = 0, a6 = 2, a7 = 4

So, sum = 9

Answer 2

Concept

An integer may be a number that may be positive, negative, or zero. samples of integers are: 1,2,-1,3,4,-10,etc.

Given

a1,a2,a3,a4,a5,a6,a7 are unique integers.

To Find

We have to seek out the worth of a2/2!+a3/3!.

Explanation

let the integers be:

a1=2

a2=3

a3=4

a4=6

a5=-7

a6=8

a7=-9

These are the unique integers because all the integers all are different.

The given expression is that we've to seek out the worth is a2/2!+a3/3!

=3/3!+4/4!

=3/3*2*1+4/4*3*2*1

(! means factorial which is simplified as multiplication of decreased numbers means 3!=3*2*1)

=3/6+4/24

=1/2+1/6

=(3+1)/6

=4/6

=2/3

Hence the worth of the expression is 2/3.

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