Question

If a1, a2, a3, a4... till (2n)th term are in A.P. then the value of {1/a1a3+1/a3a5+1/a5a7+...+1/a(2n-3)a(2n-2)}/{1/a2a4+1/a4a6+1/a6a8+...+a(2n-2)a(2n)} is?​

Answer 1

Answer:

If a

1

,a

2

,a

3

,....a

2n+1

are in A.P. then

a

2n+1

+a

1

a

2n+1

−a

1

+

a

2n

+a

2

a

2n

−a

2

+...+

a

n+2

+a

n

a

n+2

−a

n

is equal to