Question

if a1, a2, a3..........are 8n AP such that a4÷a7=3÷2, then the 13th term of the AP is?​

Answer 1

a4/a7= 3/2

a+3d/a+6d= 3/2 cross multiplying

2(a+3d)=3(a+6d)

2a+6d= 3a+18d

3a+18d=2a+6d

3a-2a=6d-18d

a=-12d

a+12d=0

a13=0