If a1,a2,a3..... are in AP, such that a1+a7+a16=40, then find the sum of the first 15 terms of the AP
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12
Answer:
200
Step-by-step explanation:
a1+a7+a16=(a)+(a+6d)+(a+15d)=40
3a+21d=40
a+7d=(40/3)
Sum of first 15 terms
=15*(2a+14d)/2
=15*(a+7d)
=15*(40/3)
=200
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