Question

If a1 cos theta + b2 sin theta +c1=0 ​and a2 cos theta+b2sin theta +c2=0

Answer 1

Answer:

answer is 29

Step-by-step explanation:

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Answer 2

correct question:

if a_1 cos theta + b_2 sin theta +c_1=0 ​and a_2 cos theta+b_2 sin theta +c_2=0 then, (b_1 c_2 - b_2 c_1)² + (c_1 a_1 - c_2 a_1)² = ?

answer:

given, cos theta / (b_1 c_2 - c_1 b_2) = sin theta/(c_1 a_2 - a_1 c_2) = 1/(a_1 b_2 - b_1 a_2)

cos theta = (b_1 c_2 - b_2 c_1)/(a_1 b_2 - a_2 b_1)

sin theta = (c_1 a_2 - c_2 a_1)/(a_1 b_2 - a_2 b_1)

sin² theta + cos² theta = 1

by substituting the values we will get;

(c_1 a_2 - c_2 a_1)² + (b_1 c_2 - b_2 c_1)² =  (a_1 b_2 - a_2 b_1)²

ANSWER = (a_1 b_2 - a_2 b_1)²

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