Question

If A16,4) and B (2,6) are two points lying
on the perimeter of a circle with centre
at (t , k²1), find
and the value of t?​

Answer 1

$\large{\red{ \mathrm{correct \: question}}}$

If A16,4) and B (2,6) are two points lying

on the perimeter of a circle with centre

at (t , t² - 1), find

the value of t?

$\\ \large{\red{ \mathrm{concept}}}$

• radius of circles are equal
• distance formula

$\large{\red{ \mathrm{answer}}}$

apply distance formula

$t^2-32t+256+t^4-10t^2+25=t^2-4t+4+t^4-14t^2+49</p><p>$

$-3t+256-10t^2+25</p><p>=-4t+4-14t^2+49</p><p>4t^2+t+228$

we get

$\\ \: \frac {t= -1\pm\sqrt{-3647}}{8}</p><p></p><p>$

imaginary value of the obtained.