if a2+1/a2= 2 then a-1/a=
SakshaM725:
question is incomplete
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Answered by
1
Hi ,
a² + 1/a² = 2
a² + 1/a² - 2 = 0
a² + 1/a² - 2 × a × 1/a = 0
( a - 1/a )² = 0
a - 1/a = 0
I hope this helps you.
: )
a² + 1/a² = 2
a² + 1/a² - 2 = 0
a² + 1/a² - 2 × a × 1/a = 0
( a - 1/a )² = 0
a - 1/a = 0
I hope this helps you.
: )
Answered by
0
if
(a^2 + 1)/a^2 = 2
(a + 1)^2 - 2a = 2a^2 [(a + b)^2 = a^2+b^2+2ab]
(a + 1)^2 = 2a^2 + 2a
(a + 1)^2 = 2a (a + 1)
(a + 1)(a + 1)/(a + 1) = 2a
a + 1 = 2a
1 = 2a - a
a = 1
On putting the value of a in
(a - 1)/ a
= 1 - 1 / 1
= 0
(a^2 + 1)/a^2 = 2
(a + 1)^2 - 2a = 2a^2 [(a + b)^2 = a^2+b^2+2ab]
(a + 1)^2 = 2a^2 + 2a
(a + 1)^2 = 2a (a + 1)
(a + 1)(a + 1)/(a + 1) = 2a
a + 1 = 2a
1 = 2a - a
a = 1
On putting the value of a in
(a - 1)/ a
= 1 - 1 / 1
= 0
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