Math, asked by samarthbhandari91, 10 months ago

if a²+1/a² = 40 , find the value of 2a³+7a-2/a³-7/a​

Answers

Answered by Anonymous
1

It is given that ,

( a² + 1 )/a = 4

a²/a + 1/a = 4

a + 1/a = 4 ------( 1 )

Now ,

2a³ + 2/a³

= 2 ( a³ + 1/a³ )

= 2 [ ( a + 1/a )³ + 3( a + 1/a )

= 2 [ 4³ + 3 × 4 ]

= 2 [ 64 + 12 ]

= 2 × 76

= 152

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Answered by kanchanb2510
10

Answer:

It is : 104

Step-by-step explanation:

(a²+1)/a=4

=> a+1/a=4

=> (a+1/a)³=(4)²

=> a³+1/a³+3*4=64

=> a³+1/a²=52

=> 2(a³+1/a³)=2*52

=> 2a³+2/a³=104

Hence, answer is 104.

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