If (a2- 1)x² + (a – 1)x + a2-4a + 3 = 0 is an identity in x, then find the value of a.
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4
Answer:
1
Step-by-step explanation:
(a
2
−1)x
2
+(a−1)x+a
2
−4a+3=0
(a−1)[(a+1)x
2
+x+(a−3)]=0
a=1
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