If a²=16,b²=3,c²=81*3 find the value of abc
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given that
a² = 16
a = √16
a = 4
b² = 3
b = √3
c² = 81 × 3
c² = √3× 3× 3× 3× 3
c = 9√3
Therefore ,
the value of abc
a × b × c
4 × √3 × 9√3
108
The value is 108
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