Math, asked by crazyslayer61, 9 months ago

If a²=16,b²=3,c²=81*3 find the value of abc​

Answers

Answered by Anonymous
8

\huge\tt\green{SolUtionv-}

given that

a² = 16

a = √16

a = 4

b² = 3

b = √3

c² = 81 × 3

c² = √3× 3× 3× 3× 3

c = 9√3

Therefore ,

the value of abc

a × b × c

4 × √3 × 9√3

108

The value is 108

Similar questions