Question

if a²+1upon a²=7,find:​

Answer 1

Answer:

⟹(a−1a)2=25

⟹a2+1a2−2=25

⟹a2+1a2+2=29

⟹(a+1a)2=29

⟹a+1a=±29−−√

Now,

a2−1a2=(a+1a)⋅(a−1a)

⟹a2−1a2=±29−−√⋅5

Hence,

⟹a2−1a2=±529−−√