If a²-2a-1=0, then find: a-1/a
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a^2-2a+1=2
(a-1)^2=(√2)^2
a-1=+ √2 and a-1=-√2
a=√2+1 and a=1-√2
For a=√2+1, 1/a=1/(√2+1)=(√2-1)/{(√2+1)(√2-1)}=√2-1
a-(1/a)=√2+1-(√2-1)=2
For a=1-√2, 1/a=1/(1-√2)=(1+√2)/{(1-√2)(1+√2)}=
1+√2/(1-2)=-1-√2
a-1/a=1-√2-(-1-√2)=2
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