If a2-3a+1=0 and a is not equal to 0. Find a+I upon a
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Answered by
2
Answer:
3
Step-by-step explanation:
⇒ a² - 3a + 1 = 0
⇒ a² + 1 = 3a
Divide both sides by a:
⇒ (a² + 1)/a = 3a
⇒ (a²/a) + (1/a) = 3a/a
⇒ a + (1/a) = 3
Hence, the value of a + 1/a is 3
Method 2: if you're familiar with roots. Let the roots be x and y.
Product of roots = xy = 1 ⇒ y = 1/x
Sum of roots = x + y = - (-3) = 3
Thus,
⇒ x + y = 3 ⇒ x + 1/x = 3
Replacing x with a(as x represents a):
⇒ a + 1/a = 3 required value
Answered by
7
a²-3a+1 = 0 αnd α is not equal to 0
- a²+ 1 = 3a
- a² + 1 / a = 3 a
- a²/a + 1 / a = 3 a/a
- a + 1 / a = 3
So, a+1/a = 3
a+1/a = 3
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hope it helps
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