If a²-3a+1=0 , find (i) a²+1/a² (ii) a³+1/a³ !!!!
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Hello friend your answer is....
first we solve ,
a ^ 2 - 3a + 1 = 0
a^2 = 3a - 1
and now ,
( I ) a ^2 + 1 / a^2
PUT THE VALUE OF a^2 in equation.
= ( 3a - 1 ) + 1 / ( 3a - 1 )
= 3a - 1 + 1 / 3a - 1/1
= 3A - 1 + 1 / 3a - 0
= 3a + 1 / 3a
And now ( ii )
a ^3 + 1 / a^3
Put the value of a^2
can we write the equation
( a^2 )
first we solve ,
a ^ 2 - 3a + 1 = 0
a^2 = 3a - 1
and now ,
( I ) a ^2 + 1 / a^2
PUT THE VALUE OF a^2 in equation.
= ( 3a - 1 ) + 1 / ( 3a - 1 )
= 3a - 1 + 1 / 3a - 1/1
= 3A - 1 + 1 / 3a - 0
= 3a + 1 / 3a
And now ( ii )
a ^3 + 1 / a^3
Put the value of a^2
can we write the equation
( a^2 )
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