Math, asked by gurmansingh387, 2 months ago

х
If
a² + 3ab² x² + 3xy²
3a²b +63 3x²y + y3
+ ?
show that
у
b
a

Answers

Answered by RamArora
0

Answer:

We have

a3 + 3ab2/b3 + 3a2b = 63/62

App. Componendo and Dividendo

a3 + 3ab2 + b3 + 3a2b/ a3 + 3ab2 - b3 - 3a2b = 63 + 62/63 – 62

a3 + b3 + 3ab2 + 3a2b/a3 + 3ab2 - b3 - 3a2b = 125/1

(a + b)3/(a – b)3 = 125/1

a + b/a – b = 5/1

Again Applying Componendo and Dividendo

a + b + a – b/a + b – a + b = 5 + 1/5 – 1

2a/2b = 6/4

a : b = 3 : 2

Step-by-step explanation:

hope it helps mark be the BRAINLIEST

Answered by durva83
0

Answer:

that a3 + 3ab2/b3 + 3a2b = 63/62

Using Componendo and Dividendo find a : b.

step by step explaination:

We have

a3 + 3ab2/b3 + 3a2b = 63/62

App. Componendo and Dividendo

a3 + 3ab2 + b3 + 3a2b/ a3 + 3ab2 - b3 - 3a2b = 63 + 62/63 – 62

a3 + b3 + 3ab2 + 3a2b/a3 + 3ab2 - b3 - 3a2b = 125/1

(a + b)3/(a – b)3 = 125/1

a + b/a – b = 5/1

Again Applying Componendo and Dividendo

a + b + a – b/a + b – a + b = 5 + 1/5 – 1

2a/2b = 6/4

a : b = 3 : 2

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