Question

If a2 + 4a + x = (a + 2)2, find the value of x.
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Answer 1

Answer:

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Answer 2

Given :-

$a {}^{2} + 4a + x = (a + 2) {}^{2}$

To find :-

Value of x

SOLUTION:-

First expand the (a + 2)² in RHS

It is in form of (a + b)² = a² + 2ab + b² Since,

$a {}^{2} + 4a + x = a {}^{2} + 2(2a) + (2) {}^{2}$

$a {}^{2} + 4a + x = a {}^{2} + 4a + 4$

Tranposing all terms to LHS

$a {}^{2} + 4a + x - a {}^{2} - 4a - 4 = 0$

$a {}^{2} - a {}^{2} + 4a - 4a + x - 4 = 0$

$x - 4 = 0$

$x = 4$

So, the value of x is 4

Know more :-

Some algebraic identities:-

(a+ b)² = a² + b² + 2ab

( a - b )² = a² + b² - 2ab

( a + b )² + ( a - b)² = 2a² + 2b²

( a + b )² - ( a - b)² = 4ab

( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca

a² + b² = ( a + b)² - 2ab

(a + b )³ = a³ + b³ + 3ab ( a + b)

( a - b)³ = a³ - b³ - 3ab ( a - b)

If a + b + c = 0 then a³ + b³ + c³ = 3abc