If a2+a+1=0 then a3??
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Hey!
Here's the solution.
given= a+a^2+a^3–1=0
a+a^2+a^3=1
Taking ‘a’ common in LHS.
a(1+a+a^2)=1
1+a+a^2=1/a ………..(1)
Now what you need to find is a^3+1/a
So substitute the value of 1/a from equation (1)
This gives us a^3+ 1+a+a^2
=a^3+a^2+a+1
=1+1
= 2
So 2 is the required answer.
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