Question

If a²=b+c,b²=c+a and c²=a+b,then the value of (1/1+a)+(1/1+b)+(1/1+c) is
How to solve quickly

Answer 1

Answer:

sorry i dont know ...

Answer 2

Step-by-step explanation:

a² = b + c

b² = c + a

c² = a + b

a² - b² = b - a      =>  (a - b) (a + b) = b - a

               =>  a + b  = -1    or  a = b

1)  a + b ≠ - 1      as  c²  is not negative, if c is a real number.

         a = b  =>  c² = 2 a

     similarly, b = c    =>  a² = 2 b            (as  b+c ≠ -1, as a² is non negative)

       and  c = a =>  b² = 2 a

   so we get a = b = c = 2