If a²+b²=13 and ab=16, find a+b and a-b
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0
Answer:
a+b=45 a-b= -19
Step-by-step explanation:
Answered by
1
Answer:
( a+ b)² = a²+ 2ab +b²
( a+ b)² = a² +b² + 2ab
Given a²+b²=13
and ab=16
( a+ b)² = a² +b² + 2ab
( a+ b)² = 13 + 2×16
( a+ b)² = 13 + 32
( a+ b)² = 45
a+ b = √45
and
a+ b)² = a²+ 2ab +b²
( a+ b)² = a² +b² + 2ab
Given a²+b²=13
and ab=16
( a- b)² = a² +b² - 2ab
( a- b)² = 13 - 2×16
( a - b)² = 13 - 32
( a- b)² = - 19
i² = -1. The imaginary number,
( a- b)² = 19i²
(a-b) = √19 i
Step-by-step explanation:
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