Math, asked by Oihik8, 1 year ago

If a2+b2=13 and ab =6 find
(i) a + b
(i) a - b

Answers

Answered by anju7699
112

(I) (a+b)^2= a^2+b^2+2ab

= 13+2×6

=25

(a+b) = √25 = ±5

(2) (a-b)^2= a^2+b^2 - 2ab

= 13 - 2×6

= 1

(a-b) = √1= ±1

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Answered by ShiningSilveR
56
hey mate here's ur answer

given: a² + b² = 13 and ab = 6

we know that

(a+b)² = a² + b² + 2ab

=> (a+b)² = 13 + 2(6)

=> (a+b)² = 13 + 12

=> a + b = √25

=> a + b = ±5

also,

(a-b)² = a² + b² - 2ab

=> (a-b)² = 13 - 2(6)

=> (a-b)² = 13 - 12

=> a - b = √1

=> a - b = ±1

Oihik8: thank you very much
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