If a2+b2=13 and ab =6 find
(i) a + b
(i) a - b
Answers
Answered by
112
(I) (a+b)^2= a^2+b^2+2ab
= 13+2×6
=25
(a+b) = √25 = ±5
(2) (a-b)^2= a^2+b^2 - 2ab
= 13 - 2×6
= 1
(a-b) = √1= ±1
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Oihik8:
Thank you so much
Answered by
56
hey mate here's ur answer
given: a² + b² = 13 and ab = 6
we know that
(a+b)² = a² + b² + 2ab
=> (a+b)² = 13 + 2(6)
=> (a+b)² = 13 + 12
=> a + b = √25
=> a + b = ±5
also,
(a-b)² = a² + b² - 2ab
=> (a-b)² = 13 - 2(6)
=> (a-b)² = 13 - 12
=> a - b = √1
=> a - b = ±1
given: a² + b² = 13 and ab = 6
we know that
(a+b)² = a² + b² + 2ab
=> (a+b)² = 13 + 2(6)
=> (a+b)² = 13 + 12
=> a + b = √25
=> a + b = ±5
also,
(a-b)² = a² + b² - 2ab
=> (a-b)² = 13 - 2(6)
=> (a-b)² = 13 - 12
=> a - b = √1
=> a - b = ±1
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