If a2 + b2 = 13 and ab = 6, find :
(i) a + b (ii) a - b
(iii) a2- b2 (iv) 3(a + b)2 -2(a - b)2
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Step-by-step explanation:
a2 + b2 = 13 and ab = 6
(i) (a + b)2 = a2 + b2 + 2ab = 13 + 2×6 = 25
=> a + b = 5
(ii) (a - b)2 = a2 + b2 - 2ab = 13 - 2×6 = 1
=> a - b = 1
(iii) a2- b2 = (a + b)(a - b) = 5×1 = 5 [from (i) and (ii)]
(iv) 3(a + b)2 -2(a - b)2 = 3×25 - 2×1 = 73 [from (i) and (ii)]
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same samesamesamesame
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