Math, asked by krithikaks5137, 1 year ago

If a2+b2=177and ab=54 then find the value of a+b/a-b?

Answers

Answered by chakri369
0

Answer:

(a+b)2=a2+b2+2ab

(a+b)2=177+2(54)

(a+b)2=177+108

(a+b)2=285

a+b=√285

a-b=√69

a+b/a-b=√285/69

a+b/a-b=√4.13

a+b/a-b=2(approx)

Answered by harshvardhan9637
1

Answer:

(a+b)2=a2+b2+2ab

(a+b)2= 117+2×54

(a+b)2= 225

a+b= √225

a+b= 15. ------(1)

again, (a-b)2= a2+b2-2ab

(a-b)2 = 117-2×54

(a-b)2= 9

a-b= √9

a-b= 3. -------(2)

Now, a+b/a-b

= 15/3. {from equation (1)&(2)}

= 5.

hence, value of a+b/a-b is 5.

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