If a2+b2 = 24and ab =10 find a(a+b)^2 +3(a-b)^2
Answers
Answer:
The answer is 202
Step-by-step explanation:
I explained and solved the problem in picture.
Answer:
The value of the given expression is either 202.08 or 114.08.
Step-by-step-explanation:
We have given that,
- a² + b² = 24
- ab = 10
We have to find the value of
a ( a + b )² + 3 ( a - b )²
Let this expression be P.
∴ P = a ( a + b )² + 3 ( a - b )²
⇒ P = a ( a² + 2ab + b² ) + 3 ( a² - 2ab + b² )
⇒ P = a ( a² + b² + 2 * ab ) + 3 ( a² + b² - 2 * ab )
⇒ P = a ( 24 + 2 * 10 ) + 3 ( 24 - 2 * 10 )
⇒ P = a ( 24 + 20 ) + 3 ( 24 - 20 )
⇒ P = a * 44 + 3 * 4
⇒ P = 44a + 12
Now,
ab = 10
⇒ b = 10 / a
By using this value, we get,
a² + b² = 24
⇒ a² + ( 10 / a )² = 24
⇒ a² + ( 10² / a² ) = 24
⇒ a² + ( 100 / a² ) = 24
⇒ ( a² * a² + 100 ) / a² = 24
⇒ a⁴ + 100 = 24a²
⇒ a⁴ - 24a² + 100 = 0
By substituting a² = x, we get,
⇒ x² - 24x + 100 = 0
Comparing with ax² + bx + c = 0, we get,
- a = 1
- b = - 24
- c = 100
By quadratic formula,
Now,
Also,
Now, by using a = 4.32,
P = 44a + 12
⇒ P = 44 * 4.32 + 12
⇒ P = 190.08 + 12
⇒ P = 202.08
Now, by using a = 2.32,
P = 44a + 12
⇒ P = 44 * 4.32 + 12
⇒ P = 102.08 + 12
⇒ P = 114.08
∴ The value of the given expression is either 202.08 or 114.08.