if a²+b²=34and ab=12, find 3(a+b)²+5(a-b)²
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if a²+b²=34and ab=12, find 3(a+b)²+5(a-b)².
3(a+b)²+5(a-b)²
= 3 (a²+ b² + 2ab) + 5(a²+ b² - 2ab)
Now putting the value we will get ,
= 3 ( 34 + 2×12) + 5 ( 34 - 2× 12)
= 3 ( 34 + 24 ) + 5 ( 34 - 24)
= (3 × 58) + (5 × 10).
= 174 + 50.
= 224 ( ans )
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