Question

if a²+b²=4 and (a-b)²=36 then find value of a b.​

Answer 1

Step-by-step explanation:

ur answer is in the above attachment

Answer 2

Answer:

Given ,

• a² + b² = 4 ———(i)

• (a - b)² = 36 ———(ii)

From $\tt{eq}^{n}$(ii) ,

a² – 2ab + b² = 36

→ a² + b² – 2ab = 36

→ 4 – 2ab = 36 {from $\tt{eq}^{n}$(i)}

→ – 2ab = 36 – 4

→ – 2ab = 32

→ ab = –32/2

→ ab = –16

Hence the value of ab is –16