Question

if a²+b²=4 then how a+b=√6
​

Answer 1

Answer:

ab =1

Step-by-step explanation:

${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab$

$given$

${a}^{2} + {b}^{2} = 4 \\ a + b = \sqrt{6}$

$then$

${ \sqrt{(6)} }^{2} = 4 + 2ab$

$6 - 4 = 2ab \\ 2ab = 2 \\ ab = 2 \div 2 = 1$

hope it helps..