Question

if a2+b2=41 and ab=4 find a+b and a-b

Answer 1

$(a + b) {}^{2} = {a}^{2} + {b}^{2} + 2ab \\ (a + b) = \sqrt{41 + 8} = + - 7.....(ans) \\ \\ (a + b) {}^{2} - 4ab = (a - b) {}^{2} \\ \sqrt{} 49 - 4(4) = a - b$