Question

If a2+b2 = 41 and ab = 4 , find the value of a+b

Answer 1

Step-by-step explanation:

$( {a}^{2} + {b}^{2} ) = {a}^{2} + {b }^{2} + 2ab$

$now$

${a}^{2} + {b}^{2} = 41 \: \: and \: \: ab = 4$

$({a + b})^{2} = 41 + 2 \times 4 =$

$= 41 + 8 = 49$

$( {a + b})^{2} = 49$

$a + b = \sqrt{49}$

$a + b = 7$

Answer = a + b = 7