Math, asked by mathseek, 2 months ago

If a2+b2 = 41 and ab = 4 , find the value of a+b

Answers

Answered by eashu53
1

Step-by-step explanation:

( {a}^{2}  +  {b}^{2} ) =  {a}^{2}  +  {b }^{2}  + 2ab

now

 {a}^{2}  +  {b}^{2}  = 41 \:  \: and  \: \: ab = 4

 ({a + b})^{2}  = 41 + 2 \times 4 =

 = 41 + 8 = 49

( {a + b})^{2}  = 49

a + b =  \sqrt{49}

a + b = 7

Answer = a + b = 7

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