Question

If a2 + b2 = 4b + 6a 13, then what is the value of a + b

Answer 1

it is given that, a² + b² = 4a + 6b - 13

⇒a² + b² - (4a + 6b - 13) = 0

⇒a² + b² - 4a - 6b + 13 = 0

⇒a² - 4a + 4 + b² - 6b + 9 = 0

⇒a² - 2.2.a + (2)² + b² - 2.3.b + (3)² = 0

we know, from algebraic identities,

• a² - 2ab + b² = (a - b)²

⇒(a - 2)² + (b - 3)² = 0

(a - 2)= 0 ⇒a = 2 and (b - 3) = 0 ⇒b = 3

then, (a + b) = 2 + 3 = 5

hence, value of (a + b) = 5

Answer 2

Answer:

Step-by-step explanation: