if a² + b²= 58 and a b= 21 find the value of a + b and a -b
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Given, (a+b)^2 = a² + b²+2ab
(a+b)^2 = 58 + 2(21)
(a+b)^2 = 100
∴ a+b = 10
(a-b)^2 = a² + b²-2ab
(a-b)^2 = 58 - 2(21)
(a-b)^2 = 16
∴ a-b = 4
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