if a2 +b2=65 ,ab=8 find a2-b2
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We know that
(a+b)²= a²+b²+2ab
(a+b)²= 65 + 2(8)
(a+b)²= 65+16
(a+b)²= 81
Taking square root to both sides we get;
(a+b)= +/- 9
We know that
(a-b)²= a²+b²-2ab
(a-b)²= 65-2(8)
(a-b)²= 65-16
(a-b)²= 49
Taking square root to both side we get;
(a-b)= +/- 7
Taking the formula of;
a²-b²= (a+b)(a-b)
a²-b²=9×7
a²-b²= 63
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