Math, asked by rr3378554, 18 hours ago

If a2+ b2 = 80 and ab = 32, then find the value of 1/a + 1/b​

Answers

Answered by narahariananya
1

Answer:

Step-by-step explanation:a2 + b2 = 80 and ab = 32

(a + b)2 = a2 + b2 + 2ab = 80 + 2 × 32 = 80 + 64 = 144

⇒ a + b = 12

(a – b)2 = a2 + b2 – 2ab = 80 – 2 × 32 = 80 – 64 = 16

⇒ a – b = 4

a-b = 4 = 1 = 0.333

a+b 12 3

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